Sample Visitor Welcome Letter For Church Margin Of Error, The Rule For Sample Proportions?
Margin of Error, The rule for sample proportions? - sample visitor welcome letter for church
Asique Ok the question is: 335 visitors were carried out as part of an investigation by the McDowell Group, were interviewed, 78 percent are "very satisfied" with their time in the city, they visited.
That's what I wanted to know:
The reported margin of error was 5.5 percent. Are you with your bill?
Construct a confidence interval 95% to the actual proportion of visitors who are "very satisfied" with their visit. (This happened to 3.1% - 6.1%, is that true?)
Do you think that was the "rule of sampling units used to the error rate or the formula by calculating the sample proportions?
I came with an error rate of 2.68% I think?
I do not understand how they arrived at 5.5%!
Under the assumption that the sample may be representative for all visitors to several days, you might reasonably conclude that over 50% of the attendees were "very satisfied" with this visit? Is it reasonable to infer that more than 75% of all visitors "very satisfied"?
|
1 comments:
5.5% seems appropriate for an n = 335 sample size.
The 95% confidence interval is probably 72.5% -83.5% of visitors very satisfied with their day happy. (Margin of error is the radius of a confidence interval for a statistic such an investigation.)
It would be impossible to achieve an error rate of 2.86% in a sample that small.
So one can reasonably conclude that over 50% of the attendees were "very satisfied", but could not say with certainty that, over 75% of the attendees were "very satisfied".
Post a Comment